Question

An element (X) has an equal number of neutrons as are in $_{32}{S^{16}}$ and has $31$ nucleons. The position of element (X) in periodic table is
(A) $3rd$ period, $16th$ group
(B) $4th$ period, $14th$ group
(C) $3rd$ period, $15th$ group
(D) $4th$ period, $15th$ group​

Answer 1

Hint : While a lot of what is in the intermittent table is steady and improbable to change, the IUPAC association is answerable for choosing what should be changed. They have made models for what comprises the revelation of another component. Nuclear loads found inside an occasional table one may believe are consistent. Truly nuclear loads have changed as an element of time

Complete Answer
First let us start with the neutrons value in $_{32}{S^{16}}$ and that is calculated as:
Neutrons in $_{32}{S^{16}}$ $= {{ }}32 - 16{{ }} = {{ }}16.$
Now let us calculate the total number of neutrons
$\Rightarrow$ total number of neutrons = $31$
That is the total number of protons and neutrons in the element is equal to $31$
$\Rightarrow$ protons + neutrons = $31$
Let us calculate the protons from the above equation. And this can be done by:
Protons = $31 - 16$ which is equal to;
Protons = $15$ .
As we know that the protons is equal to the atomic number of the substance
$\Rightarrow$ number of protons = atomic number = $15$
The atomic number $15$ element is Phosphorus which belongs to the 3rd period 15th group.
Thus, the correct answer is option C.

Additional Information
A period in the occasional table is a line of compound components. All components straight have a similar number of electron shells. Each next component in a period has one more proton and is less metallic than its archetype. Organized along these lines, gatherings of components in a similar segment have comparative compound and actual properties, mirroring the occasional law. There are right now seven complete periods in the intermittent table, containing the $118$ known components. Any new components will be put into an eighth period.

Note
No component of the eighth time frame has yet been blended. A g-block is anticipated. It isn't clear if all components anticipated for the eighth time frame are truth be told actually conceivable. There may consequently be no eighth period.