Question

An element of $0.05 \hat { \mathrm { i } }$ m is placed at the origin as shown in figure which carries a large current of 10 A. The magnetic field at a distance of 1 m in perpendicular direction is

• A. 4.5 × 10-8 T
• B. 5.5 × 10-8 T
• C. 5.0 × 10-8 T
• D. 7.5 × 10-8 T

Answer 1

Answer: (C)

5.0 × 10-8 T

Answer 2

Here,

$\sin \theta = \sin 90 ^ { \circ } = 1$

$\therefore \mathrm { dB } = 10 ^ { - 7 } \times \frac { 10 \times 0.05 \times 1 } { ( 1 ) ^ { 2 } } = 0.50 \times 10 ^ { - 7 } = 5.0 \times 10 ^ { - 8 } \mathrm {~T}$