Question

An element occurring in the $bcc$ structure has $12.08 \times 10^{23}$ unit cells. The total number of atoms of the element in these cells will be.

• A. $24.16 \times 10^{23}$
• B. $36.18 \times 10^{23}$
• C. $6.04 \times 10^{23}$
• D. $12.08 \times 10^{23}$

Answer 1

Answer: (A)

$24.16 \times 10^{23}$

Answer 2

There are two atoms in a bcc unit cell.

So, number of atoms in $12.08 \times 10^{23}$unit cells

$= 2 \times 12.08 \times 10^{23}$ $= 24.16 \times 10^{23}atom$.