An element occuring in the bcc structure has (12.08 \times 1... | Chemistry | SolveeIt | Solveeit

Today, August 23

Question

An element occuring in the bcc structure has $12.08 \times 10^{23}$ unit cells. The total number of atoms of the element in these cells will be

A

$24.16 \times 10^{23}$

B

$36.18 \times 10^{23}$

C

$6.04 \times 10^{23}$

D

$12.08 \times 10^{23}$

Answer

$24.16 \times 10^{23}$

Explanation

Solution

There are two atoms in a bcc unit cell. So, number of atoms in
$12.08 \times 10^{23}$ unit cells
$= 2 \times 12.08 \times 10^{23} = 24.16 \times 10^{23}$ atoms.