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Question: An element (atomic mass = 100 g/mole) having bcc structure has unit cell edge 400 pm. The density of...

An element (atomic mass = 100 g/mole) having bcc structure has unit cell edge 400 pm. The density of the element is (no. of atoms in bcc(Z) = 2).

A

2.144 g/cm3

B

5.2 g/cm3

C

7.289 g/cm3

D

10.376 g/cm3

Answer

5.2 g/cm3

Explanation

Solution

density = Z×MNA×a3=2×1006×1023×(400×1010)3\frac{Z \times M}{N_{A} \times a_{3}} = \frac{2 \times 100}{6 \times 10^{23} \times (400 \times 10^{- 10})^{3}}= 5.2 g/cm