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Question

Chemistry Question on The solid state

An element (atomic mass 100g/mol100 \,g /\, mol ) having BCCBCC structure has unit cell edge 400pm400\, pm. The density of element is (No. of atom in BCC(Z)=2BCC ( Z )=2 ).

A

10.376g/cm310.376\, g/cm^3

B

5.1888g/cm35.1888 \,g/cm^3

C

7.289g/cm37.289\, g/cm^3

D

2.144g/cm32.144 \,g/cm^3

Answer

5.1888g/cm35.1888 \,g/cm^3

Explanation

Solution

No. of atoms per unit cell in b.c.c.b.c.c. lattice (n)=2(n) = 2

Density, d=n×Ma3×NAd = \frac{n \times M}{a^3 \times N_A}
=2×100(4×108cm)3×6.02×1023= \frac{2\times 100}{(4\times 10^{-8}\,cm)^3 \times 6.02 \times 10^{23}}
=20038.528= \frac{200}{38.528}
=5.19g/cm3= 5.19\,g/cm^3.