Solveeit Logo

Question

Question: An element A decays into an element C by a two step process \(A \rightarrow B +_{2}He^{4}\) and \(B ...

An element A decays into an element C by a two step process AB+2He4A \rightarrow B +_{2}He^{4} and BC+2eB \rightarrow C + 2e^{-} then

A

A and C are isotopes

B

A and C are isobars

C

B andC are isotopes

D

A nad B are isobars

Answer

A and C are isotopes

Explanation

Solution

: ZAAZ2A4B+24He{}_{Z}^{A}A \rightarrow_{Z - 2}^{A - 4}B +_{2}^{4}He

Z2A4BZA4C+210e{}_{Z - 2}^{A - 4}B \rightarrow_{Z}^{A - 4}C + 2_{- 1}^{0}e

Hence , A and C are isotopes.