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Question

Chemistry Question on Structure of atom

An electron with values 4,2,24, 2, -2 and +1/2+1/2 for the set of four quantum numbers n,l,mln,\,\,l,\,\,{{m}_{l}} and ss respectively, belongs to:

A

4s4s orbital

B

4p4p orbital

C

4d4d orbital

D

4f4f orbital

Answer

4d4d orbital

Explanation

Solution

n=4n=4 (4th Shell) l=2(dl =2(d -sub shell) ml=2(dxym_{l} =-2(d_{x y} orbital ) s=+12()s =+\frac{1}{2}(\uparrow) \ldots (i) Hence, electron belongs to 4d4 d orbital.