Question

An electron typically spends about 10^–8 sec in an excited state before it drops to lower state by emitting a photon. How many revolutions does an electron in an n = 2 Bohr orbit make in 10^–8 sec –

• A. 8 × 10⁶ rev
• B. 8 rev
• C. 10 × 10⁸ rev
• D. 80 rev

Answer 1

Answer: (A)

8 × 10⁶ rev

Answer 2

Frequency: f = $\frac { \mathrm { E } _ { 0 } } { \mathrm {~h} }$ $\frac{2}{n^{3}}$

E₀ = 13.6 eV ; n = 2

f = 0.823 × 10¹⁵ rev/sec Frequency: f = $\frac { \mathrm { E } _ { 0 } } { \mathrm {~h} }$ $\frac{2}{n^{3}}$

E₀ = 13.6 eV ; n = 2

f = 0.823 × 10¹⁵ rev/sec