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Question: An electron of mass m and charge e is accelerated from the rest through a potential difference V in ...

An electron of mass m and charge e is accelerated from the rest through a potential difference V in vacuum. Therefore, final speed of the electron would be –

A

[2eVm]1/2\left\lbrack \frac{2eV}{m} \right\rbrack^{1/2}

B

2eVm\frac{2eV}{m}

C

[eV2m]1/2\left\lbrack \frac{eV}{2m} \right\rbrack^{1/2}

D

[eVm]1/2\left\lbrack \frac{eV}{m} \right\rbrack^{1/2}

Answer

[2eVm]1/2\left\lbrack \frac{2eV}{m} \right\rbrack^{1/2}

Explanation

Solution

½ mv2 = eV

v = [2eVm]1/2\left\lbrack \frac{2eV}{m} \right\rbrack^{1/2}