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Question

Question: An electron of mass \(m\) and charge \(e\) is accelerated from rest through a potential difference V...

An electron of mass mm and charge ee is accelerated from rest through a potential difference V in vacuum. The final speed of the electron will be

A

Ve/mV\sqrt{e/m}

B

eV/m\sqrt{eV/m}

C

2eV/m\sqrt{2eV/m}

D

2eV/m2eV/m

Answer

2eV/m\sqrt{2eV/m}

Explanation

Solution

Kinetic energy K=12mv2=eVK = \frac{1}{2}mv^{2} = eV

v=2eVmv = \sqrt{\frac{2eV}{m}}