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Question: An electron of energy 1800 e V describes a circular path in magnetic field of flux density 0.4 T. Th...

An electron of energy 1800 e V describes a circular path in magnetic field of flux density 0.4 T. The radius of path is

A

2.58×10−4 m2.58 \times 10 ^ { - 4 } \mathrm {~m}

B

3.58×10−4 m3.58 \times 10 ^ { - 4 } \mathrm {~m}

C

2.58×10−3 m2.58 \times 10 ^ { - 3 } \mathrm {~m}

D

3.58×10−3 m3.58 \times 10 ^ { - 3 } \mathrm {~m}

Answer

3.58×10−4 m3.58 \times 10 ^ { - 4 } \mathrm {~m}

Explanation

Solution