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Question: An electron moving with velocity v along the axis approaches a circular current carrying loop as sho...

An electron moving with velocity v along the axis approaches a circular current carrying loop as shown in the figure. The magnitude of magnetic force on electron at this instant is-

A

μ0Z\frac { \mu _ { 0 } } { Z } eviR2X(X2+R2)3/2\frac { \mathrm { eviR } ^ { 2 } \mathrm { X } } { \left( \mathrm { X } ^ { 2 } + \mathrm { R } ^ { 2 } \right) ^ { 3 / 2 } }

B

m0 eviR2X(X2+R2)3/2\frac { \mathrm { eviR } ^ { 2 } \mathrm { X } } { \left( \mathrm { X } ^ { 2 } + \mathrm { R } ^ { 2 } \right) ^ { 3 / 2 } }

C

μ04π\frac { \mu _ { 0 } } { 4 \pi } eviR2X(X2+R2)3/2\frac { \mathrm { eviR } ^ { 2 } \mathrm { X } } { \left( \mathrm { X } ^ { 2 } + \mathrm { R } ^ { 2 } \right) ^ { 3 / 2 } }

D

0

Answer

0

Explanation

Solution

Direction of electron velocity is along magnetic lines of flux. Hence F = O