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Question

Physics Question on Magnetic Field

An electron moving in a circular orbit of radius r makes n rotations per second. The magnetic field produced at the centre has magnitude

A

μ0n2er\frac{\mu_0 n^2 e}{r}

B

μ0ne2r\frac{\mu_0 n e}{2r}

C

μ0ne2πr\frac{\mu_0 n e}{2 \pi r}

D

Zero

Answer

μ0ne2r\frac{\mu_0 n e}{2r}

Explanation

Solution

Current in the orbit, I=eTI=\frac{e}{T}
I=e(2π/ω)=ωe2π=(2πn)e2π=neI=\frac{e}{(2 \pi/{\omega})}=\frac{\omega e}{2 \pi}=\frac{(2 \pi n)e}{2 \pi}=ne
Magnetic field at centre of current carrying circular
coil is given by
B=μ0I2r=μ0ne2r\, \, \, \, B=\frac{\mu_0 I}{2r}=\frac{\mu_0 ne}{2r}