Solveeit Logo

Question

Physics Question on Moving charges and magnetism

An electron moves in a circular orbit with a uniform speed vv . It produces a magnetic field BB at the centre of the circle. The radius of the circle is proportional to

A

Bv\frac{B}{v}

B

vB\frac{v}{B}

C

vB\sqrt{\frac{v}{B}}

D

Bv\sqrt{\frac{B}{v}}

Answer

vB\sqrt{\frac{v}{B}}

Explanation

Solution

The time period of electron moving in a circular orbit
T= circumference of circular path  speed T=\frac{\text { circumference of circular path }}{\text { speed }}
=2πrv=\frac{2 \pi r}{v}
and equivalent current due to electron flow
I=eT=e(2πr/v)=ev2πrI=\frac{e}{T}=\frac{e}{(2 \pi r / v)}=\frac{e v}{2 \pi r}
Magnetic field at centre of circle
B=μ0I2r=μ0ev4πr2B=\frac{\mu_{0} I}{2 r}=\frac{\mu_{0} e v}{4 \pi r^{2}}
rvB\Rightarrow r \propto \sqrt{\frac{v}{B}}