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Question: An electron (mass \(= 9 \times 10 ^ { - 31 } \mathrm {~kg}\) charge \(= 1.6 \times 10 ^ { - 19 }\...

An electron (mass =9×10−31 kg= 9 \times 10 ^ { - 31 } \mathrm {~kg} charge =1.6×10−19= 1.6 \times 10 ^ { - 19 } coul. ) whose kinetic energy is 9×10−59 \times 10 ^ { - 5 } weber /m2/ \mathrm { m } ^ { 2 } The radius of the orbit is

A

1.25 cm

B

2.5 cm

C

12.5 cm

D

25.0 cm

Answer

25.0 cm

Explanation

Solution

=0.25 cm= 0.25 \mathrm {~cm}

=25 cm= 25 \mathrm {~cm}.