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Question: An electron is moving with a speed of \(10 ^ { 8 } \mathrm {~m} / \mathrm { sec }\) perpendicular to...

An electron is moving with a speed of 108 m/sec10 ^ { 8 } \mathrm {~m} / \mathrm { sec } perpendicular to a uniform magnetic field of intensity B. Suddenly intensity of the magnetic field is reduced to B/2. The radius of the path becomes from the original value of r

A

No change

B

Reduces to r / 2

C

Increases to 2r

D

Stops moving

Answer

Increases to 2r

Explanation

Solution

r1Br \propto \frac { 1 } { B } i.e. r1r2=B2B1r2=B1B1/2×r\frac { r _ { 1 } } { r _ { 2 } } = \frac { B _ { 2 } } { B _ { 1 } } \Rightarrow r _ { 2 } = \frac { B _ { 1 } } { B _ { 1 } / 2 } \times r= 2r