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Question

Physics Question on Atoms

An electron is moving in an orbit of a hydrogen atom from which there can be a maximum of six transitions. An electron is moving in an orbit of another hydrogen atom from which there can be a maximum of three transitions. The ratio of the velocity of the electron in these two orbits is

A

54\frac{5}{4}

B

34\frac{3}{4}

C

12\frac{1}{2}

D

21\frac{2}{1}

Answer

34\frac{3}{4}

Explanation

Solution

Number of spectral lines obtained due to transition of electrons from nn th orbit to lower orbit is,
N=n(n1)2N=\frac{n(n-1)}{2}
I case 6=n1(n11)26=\frac{n_{1}\left(n_{1}-1\right)}{2}
n1=4\Rightarrow n_{1} =4
II case 3=n2(n21)23=\frac{n_{2}\left(n_{2}-1\right)}{2}
n2=3\Rightarrow n_{2}=3
Velocity of electron in hydrogen atom in nn th orbit
vn1nv_{n} \propto \frac{1}{n}
vnvn=n2n1\frac{v_{n}}{v_{n}'} =\frac{n_{2}}{n_{1}}
v6v3=34\Rightarrow \frac{v_{6}}{v_{3}} =\frac{3}{4}