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Question

Question: An electron is moving in a circular path of radius 5.1 × 10<sup>–11</sup>*m* at a frequency of 6.8 ×...

An electron is moving in a circular path of radius 5.1 × 10–11m at a frequency of 6.8 × 1015 revolution/sec. The equivalent current is approximately

A

5.1 × 10–3A

B

6.8 × 10–3A

C

1.1 × 10–3A

D

2.2 × 10–3A

Answer

1.1 × 10–3A

Explanation

Solution

i=QT=1.6×1019×6.8×1015i = \frac { Q } { T } = 1.6 \times 10 ^ { - 19 } \times 6.8 \times 10 ^ { 15 }= 1.1 × 10–3 A