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Question

Physics Question on Electric charges and fields

An electron is moving around the nucleus of a hydrogen atom in a circular orbit of radius r. The coulomb force F\vec F between the two is- (where K=14πϵ0\frac{1}{4\pi\epsilon_0})

A

Ke2r2r^K\frac{e^2}{r^2}\hat r

B

Ke2r3r^-K \frac{e^2}{r^3}\hat r

C

Ke2r3rK\frac{e^2}{r^3}\vec r

D

Ke2r3r-K \frac{e^2}{r^3}\vec r

Answer

Ke2r3r-K \frac{e^2}{r^3}\vec r

Explanation

Solution

Coulomb force = Ke2r2(r^)K \frac{e^2}{r^2}(-\hat r)
=Ke2r3rK\frac{e^2}{r^3}\vec r