Solveeit Logo
Login

Question

Question: An electron is confined within a nucleus whose diameter 0.8 × 10<sup>–14</sup> m. The coulomb energy...

An electron is confined within a nucleus whose diameter 0.8 × 10–14 m. The coulomb energy of the electron is-

A

6.8 MeV

B

10.6 MeV

C

15 MeV

D

20.5 MeV

Answer

6.8 MeV

Explanation

Solution

R = R0A1/3

A = (R/R0)3

A = (0.4×10−141.2×10−15)3\left( \frac { 0.4 \times 10 ^ { - 14 } } { 1.2 \times 10 ^ { - 15 } } \right) ^ { 3 } I 37

For nuclei of this size no. of protons is z 372\frac { 37 } { 2 } 18.5 19

Coulomb Energy =

Energy = ×19×(1.6×10−19)24×10−15×1.6×10−19\frac { 19 \times \left( 1.6 \times 10 ^ { - 19 } \right) ^ { 2 } } { 4 \times 10 ^ { - 15 } \times 1.6 \times 10 ^ { - 19 } }eV

= 9×109×19×1.6×10−194×10−15\frac { 9 \times 10 ^ { 9 } \times 19 \times 1.6 \times 10 ^ { - 19 } } { 4 \times 10 ^ { - 15 } }

= 9 × 19 × 0.4 × 1024 × 10–19

= 68.4 × 105 eV

Coulomb energy = 6.8 MeV