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Physics Question on Dual nature of matter

An electron is accelerated under a potential difference of 182 V. The maximum velocity of electron will be (Charge of electron is 1.6×10−19C1.6 \times 10^{-19}C and its mass is 9.1×10−31kg)9.1 \times 10^{-31}kg)

A

5.65×106 ms−15.65 \times 10^6 \, ms^{-1}

B

4×106 ms−14 \times 10^6 \, ms^{-1}

C

8×106 ms−18 \times 10^6 \, ms^{-1}

D

16×10−6 ms−116 \times 10^{-6} \, ms^{-1}

Answer

8×106 ms−18 \times 10^6 \, ms^{-1}

Explanation

Solution

12mv2=eV\frac {1}{2}mv^2=eV
       12×9×10−31×v2=1.6×10−19×182\, \, \, \, \, \, \, \frac {1}{2} \times 9\times10^{-31}\times v^2=1.6 \times 10^{-19} \times 182
\hspace15mm v^2= \frac {1.6 \times 10^{-19}\times182 \times2}{9.1 \times 10^{-31}}
\hspace15mm =64 \times 10^{12}
\hspace15mm v=8 \times 10^6ms^{-1}