Question

An electron is accelerated through a potential difference of 10,000 V. Its de Broglie wavelength is. (nearly): (mt. = $9 \times 10^{-31}$ kg)

• A. $12.2\times 10^{11}$m
• B. 12.2 nm
• C. $12.2\times 10^{13}$m
• D. $12.2\times 10^{-12}$m

Answer 1

Answer: (D)

$12.2\times 10^{-12}$m

Answer 2

For an electron accelerated through a potential V $\lambda = \frac{12.27}{\sqrt{V} } \mathring A = \frac{12.27 \times10^{-10}}{\sqrt{10000}} = 12.27 \times10^{-12} m$