Question

An electron is accelerated through a potential difference of V volt. It has a wavelength l associated with it. Through what potential difference a proton must be accelerated so that its de-Brogle wavelength is the same as that of an electron? Take mass of proton to be 1837 times larger than the mass of electron.

• A. V volt
• B. 1837 V volt
• C. $\frac{V}{1837}$volt
• D. $\sqrt{1837}$V volt

Answer 1

Answer: (C)

$\frac{V}{1837}$volt

Answer 2

l _e= $\frac{h}{\sqrt{2m_{e}.eV}}$ = l_p = $\frac{h}{\sqrt{2 \times 1837m_{e}.eV^{1}}}$

̃ V = 1837 V ¢ ̃ V ¢ = $\frac{V}{1837}$volt