Question

An electron is accelerated through a potential difference of 1000 volt. The velocity acquired by the electron is –

• A. 4 × 10⁸ m/s
• B. 1.88 × 10⁷ m/s
• C. 5 × 10⁸ m/s
• D. None of these

Answer 1

Answer: (B)

1.88 × 10⁷ m/s

Answer 2

$\frac{1}{2}$mv² = eV₀

v = $\sqrt{\frac{2eV_{0}}{m}}$ = $\sqrt{\frac{2 \times 1.6 \times 10^{–19} \times 1000}{9.1 \times 10^{–31}}}$

= 1.88 × 10⁷ m/s