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Question: An electron having momentum \(30 ^ { \circ }\) with the initial velocity vector of the electron. The...

An electron having momentum 30∘30 ^ { \circ } with the initial velocity vector of the electron. The radius of the helical path of the electron in the field shall be

A

2 mm

B

1 mm

C

32\frac { \sqrt { 3 } } { 2 }mm

D

0.5 mm

Answer

0.5 mm

Explanation

Solution

The radius of the helical path of the electron in the uniform magnetic field is

=5×10−4 m=0.15×10−3 m=0.5 mm= 5 \times 10 ^ { - 4 } \mathrm {~m} = 0.15 \times 10 ^ { - 3 } \mathrm {~m} = 0.5 \mathrm {~mm}