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Question: An electron has a mass of \(9.1 \times 10^{- 31}kg\). It revolves round the nucleus in a circular or...

An electron has a mass of 9.1×10−31kg9.1 \times 10^{- 31}kg. It revolves round the nucleus in a circular orbit of radius 0.529×10−10metre0.529 \times 10^{- 10}metreat a speed of 2.2×106m/s2.2 \times 10^{6}m/s.

The magnitude of its linear momentum in this motion is.

A

1.1×10−34kg−m/s1.1 \times 10^{- 34}kg - m/s

B

2.0×10−24kg−m/s2.0 \times 10^{- 24}kg - m/s

C

4.0×10−24kg−m/s4.0 \times 10^{- 24}kg - m/s

D

4.0×10−31kg−m/s4.0 \times 10^{- 31}kg - m/s

Answer

2.0×10−24kg−m/s2.0 \times 10^{- 24}kg - m/s

Explanation

Solution

Linear momentum

=mv=9.1×10−31×2.2×106= mv = 9.1 \times 10^{- 31} \times 2.2 \times 10^{6}

=2.0×10−24kg−m/s= 2.0 \times 10^{- 24}kg - m/s