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Question

Physics Question on Electric Charge

An electron enters uniform electric field maintained by parallel plates and of value EVm1EV{{m}^{-1}} with a velocity v ms1,v\text{ }m{{s}^{-1}}, the plates are separated by a distance dd metre, then acceleration of the electron in the field is:

A

Eem\frac{Ee}{m}

B

Eem\frac{-Ee}{m}

C

Edmd\frac{Ed}{md}

D

EedmEe\frac{d}{m}

Answer

Eem\frac{Ee}{m}

Explanation

Solution

F=eEF=eE
Therefore, acceleration in electron due to force F
a=Fm=eEma=\frac{F}{m}=\frac{eE}{m}