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Question: An electron enters between two horizontal plates separated by 2mm and having a potential difference ...

An electron enters between two horizontal plates separated by 2mm and having a potential difference of 1000V. The force on electron is

A

8×10−128 \times 10^{- 12}N

B

8×10−148 \times 10^{- 14}N

C

8×1098 \times 10^{9} N

D

8×10148 \times 10^{14} N

Answer

8×10−148 \times 10^{- 14}N

Explanation

Solution

Force on electron F = QE =Q(Vd)= Q\left( \frac{V}{d} \right)

⇒ F=(1.6×10−19)(10002×10−3)=8×10−14NF = (1.6 \times 10^{- 19})\left( \frac{1000}{2 \times 10^{- 3}} \right) = 8 \times 10^{- 14}N