Solveeit Logo
Login

Question

Question: An electron entering field normally with a velocity 4 × 10<sup>7</sup> m/s, travels a distance of 0....

An electron entering field normally with a velocity 4 × 107 m/s, travels a distance of 0.10 m in an electric field of intensity 3200 V/m. What is deviation from its path?

A

1.76 mm

B

17.6 mm

C

176 mm

D

0.176 mm

Answer

1.76 mm

Explanation

Solution

Deviation y = = 1.6×10−19×3200×.10×.102×9×10−31×16×1014\frac { 1.6 \times 10 ^ { - 19 } \times 3200 \times .10 \times .10 } { 2 \times 9 \times 10 ^ { - 31 } \times 16 \times 10 ^ { 14 } }