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Question: An electron and a proton are detected in a cosmic ray experiment, the first with kinetic energy 10 k...

An electron and a proton are detected in a cosmic ray experiment, the first with kinetic energy 10 keV, and the second with 100 keV. The ratio of their speeds is :

(Where and are masses of electron and proton respectively)

A

1 me10 mp\sqrt { \frac { 1 \mathrm {~m} _ { \mathrm { e } } } { 10 \mathrm {~m} _ { \mathrm { p } } } }

B

1 mp10 me\sqrt { \frac { 1 \mathrm {~m} _ { \mathrm { p } } } { 10 \mathrm {~m} _ { \mathrm { e } } } }

C
D

1 mp10 me\frac { 1 \mathrm {~m} _ { \mathrm { p } } } { 10 \mathrm {~m} _ { \mathrm { e } } }

Answer

1 mp10 me\sqrt { \frac { 1 \mathrm {~m} _ { \mathrm { p } } } { 10 \mathrm {~m} _ { \mathrm { e } } } }

Explanation

Solution

Kinetic energy of the electron,

……(i)

Kinetic energy of the proton,

……(ii)

Divide (i) by (ii), we get

Or ve2vp2=110mpme\frac { v _ { e } ^ { 2 } } { v _ { p } ^ { 2 } } = \frac { 1 } { 10 } \frac { m _ { p } } { m _ { e } } or vevp=110mpme\frac { v _ { e } } { v _ { p } } = \sqrt { \frac { 1 } { 10 } \frac { m _ { p } } { m _ { e } } }