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Question: An electromagnetic wave is propagating along x-axis. At x =1m and t= 10s, its electric vector \(|\ov...

An electromagnetic wave is propagating along x-axis. At x =1m and t= 10s, its electric vector E=6V/m|\overrightarrow{E}| = 6V ⥂ /mthen the magnitude of its magnetic vector is

A

2×108T2 \times 10^{- 8}T

B

3×107T3 \times 10^{- 7}T

C

6×108T6 \times 10^{- 8}T

D

5×107T5 \times 10^{- 7}T

Answer

2×108T2 \times 10^{- 8}T

Explanation

Solution

: Here, E=6V/m\left| \overrightarrow{E} \right| = 6V/m

The magnitude of magnetic vector is,

B=Ec=6V/m3×108ms1=2×108T\left| \overrightarrow{B} \right| = \frac{\left| \overrightarrow{E} \right|}{c} = \frac{6V/m}{3 \times 10^{8}ms^{- 1}} = 2 \times 10^{- 8}T