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Question

Physics Question on work, energy and power

An electric pump is used to fill an overhead tank of capacity 9m39\,{{m}^{3}} kept at a height of 10m10\, m above the ground. If the pump takes 5min5 \,min to fill the tank by consuming 10kW10 \,kW power the efficiency of the pump should be (Take g=10 ms2g=10\text{ }m{{s}^{-2}} )

A

0.6

B

0.4

C

0.2

D

0.3

Answer

0.3

Explanation

Solution

Work done in raising water =mgh=mgh
or W=(volume×density)ghW=(volume\times density)gh
=(9×1000)×10×10=(9\times 1000)\times 10\times 10
or W=9×105JW=9\times {{10}^{5}}J
\therefore Useful power =workt=\frac{work}{t}
=9×1055×60=3kW=\frac{9\times {{10}^{5}}}{5\times 60}=3\,kW
Hence, efficiency
=useful powerconsuming power=\frac{useful\text{ }power}{consuming\text{ }power}
=310=30=\frac{3}{10}=30%