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Question

Physics Question on Electromagnetic induction

An electric motor operates on a 50V50\, V supply and a current of 12A12\, A. If the efficiency of the motor is 30%30\%, what is the resistance of the winding of the motor?

A

6Ω6\,\Omega

B

4Ω4\,\Omega

C

2.9Ω2.9\,\Omega

D

3.1Ω3.1\,\Omega

Answer

2.9Ω2.9\,\Omega

Explanation

Solution

I=EeRI=\frac{E-e}{R} ...(i) and η×100=(eE)×100\eta \times 100=\left(\frac{e}{E}\right) \times 100 ...(ii) 30=e50×100\therefore 30=\frac{e}{50} \times 100 [from Eqs.(ii)] R=15V\Rightarrow R=15\, V Thus, R=501512=2.9ΩR=\frac{50-15}{12}=2.9\, \Omega