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Question

Physics Question on Current electricity

An electric kettle takes 4 A current at 220 V. How much time will it take to boil 1 kg of water from temperature 20C?20^\circ C ? The temperature of boiling water is 100C100^\circ C

A

12.6 min

B

4.2 min

C

6.3 min

D

8.4 min

Answer

6.3 min

Explanation

Solution

Power =220V×4A=880= 220\, V \times 4\, A = 880 watts. =880J/s.= 880\, J/s.
Heat needed to raise the temperature of 1 kg water through 80C80^\circ C
=ms.ΔT×4.2J/cal= ms.\Delta T \times 4.2\, J/cal
=1000g×1cal/g×80×4.2J/cal.= 1000\, g \times 1\, cal/g \times 80 \times 4.2\, J/cal.
\therefore time taken =1000×1×80×4.2880=336×103880=\frac{1000\, \times 1 \times 80 \times 4.2}{880} = \frac{336 \times 10^3}{880}
=382s=6.3=382\, s=6.3 min.