Question

An electric heater of resistance 6 ohm is run for 10 minutes on a 120 volt line. The work done in this period of time is

• A. 7.2 × 103J
• B. 14.4 × 105J
• C. 43.2 × 104 J
• D. 28.8 × 104J

Answer 1

Answer: (B)

14.4 × 105J

Answer 2

H =

$W = i^{2}Rt = \frac{V^{2}t}{R} = \frac{120 \times 120 \times (10 \times 60)}{6} = 14.410^{5}Joule$