Question
Question: An electric field given by E = 4\(\widehat{i}\) – 3(y<sup>2</sup> + 2) \(\widehat{j}\) pierces Gauss...
An electric field given by E = 4i – 3(y2 + 2) j pierces Gaussian cube of side 1m placed at origin such that its three sides represent x, y and z axes. The net charge enclosed within cube is-
A
4Ī0
B
3Ī0
C
5Ī0
D
Zero
Answer
3Ī0
Explanation
Solution

E1 = 3(12 + 2) = 9
E2 = 3(0 + 2) = 6
Net flux = (9 – 6) × |x|
ϵ0q= 3
q = 3Ī0