Solveeit Logo

Question

Physics Question on Motion in a plane

An electric fan has blades of length 30 cm as measured from the axis of rotation. If the fan is rotating at 1200 rpm, the acceleration of a point on the tip of the blade is about

A

1600 ms2ms^{-2}

B

4740 ms2ms^{-2}

C

2370 ms2ms^{-2}

D

5055 ms2ms^{-2}

Answer

4740 ms2ms^{-2}

Explanation

Solution

Acceleration of a point at the tip of the blade
= centripetal acceleration
= ω2R=(2πf)2R\omega^2 R = (2\pi f)^2 R
= (2×227×120060)2×30100\left(2 \times \frac{22}{7} \times \frac{1200}{60}\right)^2 \times \frac{30}{100}
= 4740 ms2ms^{-2}