Question
Physics Question on Electric charges and fields
An electric dipole with dipole moment 2p0(i^+j^) is held fixed at the origin O in the presence of an uniform electric field of magnitude E. If the potential is constant on a circle of radius R centered at the origin as shown in figure, then the correct statement(s) is/are: (ε0 is permittivity of free space, R >> dipole size)
R=(4πε0E0P0)1/3
The magnitude of total electric field on any two points of the circle will be same
Total electric field at point A is EA=2E0(i^^+j^)
Total electric field at point B is EB=0
Total electric field at point B is EB=0
Solution
(1)P=2P0(i^+j^)
E.F. at B along tangent should be zero since circle is equipotential.
So, E0=R3K∣P∣&EB=0
So, R3=E0KP0=(4π∈0E0P0)
So R=(4π∈0E0P0)1/3
So, (1) is correct
(2) Because E0 is uniform & due to dipole E.F. is different at different points, so magnitude of total E.F. will also be different at different points.
So, (2) is incorrect
(3)EA=R32KP+R3KP=3R3KP2P0(i^+j^)
So,t(3) is wrong
(4)EB=0
so, (4) is correct