Solveeit Logo
Login

Question

Physics Question on Electric Charges and Coulomb's Law

An electric dipole with dipole moment 4×10−9Cm4 × 10^{−9} Cm is aligned at 30030^0 with the direction of a uniform electric field of magnitude 5×104NC−15 × 10^4 N C^{−1} Calculate the magnitude of the torque acting on the dipole.

Answer

Electric dipole moment, p=4×10−9Cmp = 4 × 10^{−9}Cm
Angle made by p with a uniform electric field, θ=300\theta= 30^0
Electric field, E=5×104NC−1E = 5 × 10 ^4 N C^{−1}
Torque acting on the dipole is given by the relation, τ=pEsinθ\tau= pE sin\theta
=4×10−9×5×104×sin30=20×10−5×12=10−4Nm.= 4 × 10^{-9} × 5 × 10^4 × sin 30 = 20 × 10^{-5}×\frac{1}{2} = 10^{ -4 }Nm.
Therefore, the magnitude of the torque acting on the dipole is 10−4Nm.10^{−4} N m.