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Question: An electric dipole with dipole moment \(2 \times 10^{- 19}\)cm is aligned at \(30^{o}\) with directi...

An electric dipole with dipole moment 2×10−192 \times 10^{- 19}cm is aligned at 30o30^{o} with direction of a uniform electric field of magnitude 4×104NC−14 \times 10^{4}NC^{- 1}The magnitude of the torque acting on the dipole is.

A

2×10−5Nm2 \times 10^{- 5}Nm

B

2×10−4Nm2 \times 10^{- 4}Nm

C

4×10−4Nm4 \times 10^{- 4}Nm

D

4×10−5⥂Nm4 \times 10^{- 5} ⥂ Nm

Answer

4×10−5⥂Nm4 \times 10^{- 5} ⥂ Nm

Explanation

Solution

: Here, P=2×10−9cm,θ=30oP = 2 \times 10^{- 9}cm,\theta = 30^{o}

E=4×104NC−1E = 4 \times 10^{4}NC^{- 1}

As τ=PEsin⁡θ\tau = PE\sin\theta

=2×10−9×4×104sin⁡30o= 2 \times 10^{- 9} \times 4 \times 10^{4}\sin 30^{o}

=4×10−5Nm= 4 \times 10^{- 5}Nm