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Question

Physics Question on electrostatic potential and capacitance

An electric dipole of moment p\vec{p} is lying along a uniform electric field E\vec{E}. The work done in rotating the dipole by 90^{\circ} is :-

A

p E

B

2\sqrt 2 pE

C

pE/2

D

2pE

Answer

p E

Explanation

Solution

Work done in rotating a dipole from θ1\theta_{1} to θ2\theta_{2} is
W=pE(cosθ1cosθ2)W = pE\, \left(\cos \theta_{1}-\cos \theta_{2}\right)
Here θ1=0 and θ2=90\theta_{1}=0^{\circ} \text { and } \theta_{2}=90^{\circ} therefore W=pEW = pE