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Question

Physics Question on Electric charges and fields

An electric dipole of moment pp is Iying along a uniform electric field EE. The work done in rotating the dipole by 9090^{\circ} is

A

2pE \sqrt 2 p E

B

pE2 \frac{ p E}{ 2}

C

2pE2 \,pE

D

pEpE

Answer

pEpE

Explanation

Solution

When an electric dipole is placed in an electric field EE, a torque τ=p×E\tau=p \times E acts on it. This torque tries to rotated the dipole through an angle θ\theta. If the dipole is rotated from an angle θ1\theta_{1} to θ2\theta_{2}, then work done by external force is given by W=pE(cosθ1cosθ2)W=p E\left(\cos \theta_{1}-\cos \theta_{2}\right) Putting θ1=0,θ2=90\theta_{1}=0^{\circ}, \theta_{2}=90^{\circ} in the E (i), we get W=pE(cos90cos90)W=p E\left(\cos 90^{\circ}-\cos 90^{\circ}\right) =pE(10)= pE (1-0) =pE= pE