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Question

Physics Question on Electric charges and fields

An electric dipole is placed at an angle of 3030^{\circ} with an electric field intensity 2×105N/C.2 \times 10^{5} N / C . It experiences a torque equal to 4Nm4\, Nm. The charge on the dipole, if the dipole length is 2cm2\, cm, is

A

8mC8\,mC

B

4mC4\,mC

C

6mC6\,mC

D

2mC2 \,mC

Answer

2mC2 \,mC

Explanation

Solution

τ=pEsinθ\tau= pE \sin \theta
τ=qEsinθ\tau= q \ell \operatorname{Esin} \theta
q=τEsinθq =\frac{\tau}{\ell E \sin \theta}
q=42×102×2×105×12q =\frac{4}{2 \times 10^{-2} \times 2 \times 10^{5} \times \frac{1}{2}}
q=2×103Cq =2 \times 10^{-3} C
q=2mCq =2 mC