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Question

Physics Question on electrostatic potential and capacitance

An electric dipole is placed as shown in the figure.
An electric dipole is placed as shown in the figureThe electric potential (in 102 V) at point P due to the dipole is (ε0 = permittivity of free space and 14πϵ0=K\frac{1}{4\pi\epsilon_0}=K):

A

(58)qk(\frac{5}{8})qk

B

(85)qk(\frac{8}{5})qk

C

(83)qk(\frac{8}{3})qk

D

(38)qk(\frac{3}{8})qk

Answer

(38)qk(\frac{3}{8})qk

Explanation

Solution

An electric dipole is placed as shown in the figure

v=kq2×102kq8×102v=\frac{kq}{2\times 10^{-2}}-\frac{kq}{8\times10^{-2}}

=kq[38]×102=kq[\frac{3}{8}]\times 10^{-2}

So, the correct option is (D): (38)qk(\frac{3}{8})qk