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Question

Physics Question on electrostatic potential and capacitance

An electric dipole has the magnitude of its charge as qq and its dipole moment is pp. It is placed in a uniform electric field EE. If its dipole moment is along the direction of the field, the force on it and its potential energy are respectively

A

2qE and minimum

B

qE and pE

C

zero and minimum

D

qE and maximum

Answer

zero and minimum

Explanation

Solution

An electric dipole is an arrangement of two equal an opposite charges placed at a distance 2l2 l The dipole is placed in electric field as such its dipole moment is in direction of electric field as shown in figure Now force on the charge qq is F2=qEF_{2}=q E along the direction of EE and force on charge q-q is F1=qEF_{1}=-q E in the direction opposite to EE. Since, forces on the dipole are equal and opposite, so net force on the electric dipole is zero. Now potential energy of the dipole. U=pEcosθU=-p E \cos \theta where θ\theta is the angle between direction of electric field and direction of dipole moment. θ=0\therefore \theta=0^{\circ} Hence, U=pEcos0=pEU=-p E \cos 0^{\circ}=-p E (minimum)