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Physics Question on Electric charges and fields

An electric dipole, consisting of two opposite charges of 2×10−6 C2 \times 10^{-6} \, C each separated by a distance 3 cm is placed in an electric field of 2×105 N/C2 \times 10^5 \, N/C. Torque acting on the dipole is

A

12×10−1Nm12 \times 10^{-1} N m

B

12×10−2Nm12 \times 10^{-2} N m

C

12×10−3Nm12 \times 10^{-3} N m

D

12×10−4Nm12 \times 10^{-4} N m

Answer

12×10−3Nm12 \times 10^{-3} N m

Explanation

Solution

Charges (q)=2×10−6 C(q) = 2 \times 10^{-6} \, C, Distance (d) =3cm=3× 10−2 m= 3 cm = 3 \times \, 10^{-2} \, m and electric field (E) =2×105 N/C= 2 \times 10^5 \, N/C. Torque (τ\tau) = d. E=(2×10−6)×(3×10−2)×(2×105)E =(2 \times 10^{-6}) \times (3 \times 10^{-2}) \times (2 \times 10^5) =12×10−3 Nm= 12 \times 10^{-3}\, Nm