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Physics Question on Electric charges and fields

An electric dipole coincides on ZZ-axis and its midpoint is on origin of the coordinate system. The electric field at an axial point at a distance zz from origin is E(z)E_{(z)} and electric field at an equatorial point at a distance y from origin is E(y)E_{( y)}. Here z=y>a,soE(z)E(y)=z = y > a, \, so \, \bigg | \frac{ E_{ (z) }}{ E_{(y)}} \bigg | = ...

A

1

B

4

C

3

D

2

Answer

2

Explanation

Solution

The magnitude of electric field at an axial point M at a distance z from the origin is given by
Ez=14πε0.2pz(z2a2)2| E_z | = \frac{ 1}{ 4 \pi \varepsilon_0 } . \frac{ 2 \, pz}{ (z^2 - a^2 )^2 }
For z>>a,Ez=2p4πε0z3z >> a, | E_z | = \frac{ 2p}{ 4 \pi \varepsilon_0 \, z^3 }
and, magnitude of electric field at a equatorial point N at a distance y from origin (0, 0) is given by
Ey=p4πε0(y2+a2)3/2| E_y | = \frac{ p}{ 4 \pi \varepsilon_0 ( y^2 + a^2 )^{3/2}}
For y>>a,Ey=14πε0.py3y >> a, | E_y | = \frac{ 1}{ 4 \pi \varepsilon_0 }. \frac{ p}{ y^3 }
For z=y>>az = y >> a
E(z)E(y)=2\therefore\:\: \bigg| \frac{ E_{ (z) }}{ E_{(y)}} \bigg | = 2