Question

An electric current is passed through silver nitrate solution using silver electrodes. $15.28$ g of silver was found to be deposited on cathode. What will be the weight of copper deposited on cathode if same amount of electricity is passed through copper sulphate solution using copper electrodes?

• A. $4.49g$
• B. $6.4g$
• C. $12.8g$
• D. $3.2g$

Answer 1

Answer: (A)

$4.49g$

Answer 2

Equivalent wt. of Ag = 108/1=108

Equivalent wt, of Cu = $63.5/2 = 31.75$

$\frac{Eq.wt.ofAg}{Eq.wt.ofCu} = \frac{MassofAgdeposited}{MassofCudeposited}$

$\frac{108}{31.75} = \frac{15.28}{W}$

$W = \frac{15.28 \times 31.75}{108} = 4.49g$