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Question: An electric charge 10<sup>–3</sup>mC is placed at origin (0, 0). Two points A and B are situated at ...

An electric charge 10–3mC is placed at origin (0, 0). Two points A and B are situated at (2\sqrt{2}ø2\sqrt{2}) and (2, 0) respectively. The potential difference between the points A and B will be–

A

9 volts

B

zero

C

2 volts

D

4.5 volts

Answer

zero

Explanation

Solution

VA = kqr\frac { \mathrm { kq } } { \mathrm { r } } = = kq2\frac { \mathrm { kq } } { 2 }

VB = kqr\frac { \mathrm { kq } } { \mathrm { r } ^ { \prime } } = kq(2)2+(0)2\frac { \mathrm { kq } } { \sqrt { ( 2 ) ^ { 2 } + ( 0 ) ^ { 2 } } } = kq2\frac { \mathrm { kq } } { 2 }

\ VA – VB = 0